Skudo
ENVI
Play on web

Daily Sudoku — 4 July 2026

The puzzle

  • 4 July 2026
  • Hard
  • 30 clues
Puzzle
··8····2·
7··3···85
39···5·1·
4···3····
···5·2·78
526····3·
·64··7·53
1······4·
·3·84····
Solution
658714329
741329685
392685714
487931562
913562478
526478931
864197253
179253846
235846197

Solve it in the app to get on the board

Step-by-step solution

Every cell below is filled by the same hint engine the app uses, in the order it can be deduced — 51 steps using 2 techniques.

Techniques used

  • Hidden Single — inside one row, column or box this digit fits in only one cell, so it must go there
  • Naked Single — every other digit is already used in this cell's row, column or box, so only one candidate is left
  1. R1C2 = 5 · Hidden SingleIn the top-left 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 5, R1C1 cannot hold 5.- Because row 2 already has a 5, R2C2 and R2C3 cannot hold 5.- Because row 3 already has a 5, R3C3 cannot hold 5.So 5 must go in R1C2.
  2. R2C2 = 4 · Hidden SingleIn the top-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 4, R1C1 cannot hold 4.- Because column 3 already has a 4, R2C3 and R3C3 cannot hold 4.So 4 must go in R2C2.
  3. R2C3 = 1 · Hidden SingleIn the top-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 1, R1C1 cannot hold 1.- Because row 3 already has a 1, R3C3 cannot hold 1.So 1 must go in R2C3.
  4. R3C3 = 2 · Hidden SingleIn the top-left 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 2, R1C1 cannot hold 2.So 2 must go in R3C3.
  5. R1C1 = 6 · Naked SingleLooking at R1C1:- Row 1 already has 2, 5 and 8 → ruled out.- Column 1 already has 1, 3, 4 and 7 → ruled out.- The top-left 3×3 box already has 9 → ruled out.So this cell can only be 6.
  6. R2C5 = 2 · Hidden SingleIn the top-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 2, R1C4, R1C5 and R1C6 cannot hold 2.- Because column 6 already has a 2, R2C6 cannot hold 2.- Because row 3 already has a 2, R3C4 and R3C5 cannot hold 2.So 2 must go in R2C5.
  7. R3C5 = 8 · Hidden SingleIn the top-centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 8, R1C4, R1C5 and R1C6 cannot hold 8.- Because row 2 already has a 8, R2C6 cannot hold 8.- Because column 4 already has a 8, R3C4 cannot hold 8.So 8 must go in R3C5.
  8. R1C7 = 3 · Hidden SingleIn the top-right 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 3, R1C9 cannot hold 3.- Because row 2 already has a 3, R2C7 cannot hold 3.- Because row 3 already has a 3, R3C7 and R3C9 cannot hold 3.So 3 must go in R1C7.
  9. R5C3 = 3 · Hidden SingleIn the middle-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 3, R4C2 and R4C3 cannot hold 3.- Because column 1 already has a 3, R5C1 cannot hold 3.- Because column 2 already has a 3, R5C2 cannot hold 3.So 3 must go in R5C3.
  10. R4C2 = 8 · Hidden SingleIn the middle-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because column 3 already has a 8, R4C3 cannot hold 8.- Because row 5 already has a 8, R5C1 and R5C2 cannot hold 8.So 8 must go in R4C2.
  11. R5C2 = 1 · Hidden SingleIn the middle-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because column 3 already has a 1, R4C3 cannot hold 1.- Because column 1 already has a 1, R5C1 cannot hold 1.So 1 must go in R5C2.
  12. R8C2 = 7 · Naked SingleLooking at R8C2:- Row 8 already has 1 and 4 → ruled out.- Column 2 already has 2, 3, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  13. R4C3 = 7 · Hidden SingleIn the middle-left 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 5 already has a 7, R5C1 cannot hold 7.So 7 must go in R4C3.
  14. R5C1 = 9 · Naked SingleLooking at R5C1:- Row 5 already has 1, 2, 3, 5, 7 and 8 → ruled out.- Column 1 already has 4 and 6 → ruled out.So this cell can only be 9.
  15. R6C6 = 8 · Hidden SingleIn the centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 8, R4C4 and R4C6 cannot hold 8.- Because row 5 already has a 8, R5C5 cannot hold 8.- Because column 4 already has a 8, R6C4 cannot hold 8.- Because column 5 already has a 8, R6C5 cannot hold 8.So 8 must go in R6C6.
  16. R6C4 = 4 · Hidden SingleIn the centre 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 4, R4C4 and R4C6 cannot hold 4.- Because column 5 already has a 4, R5C5 and R6C5 cannot hold 4.So 4 must go in R6C4.
  17. R1C6 = 4 · Hidden SingleIn the top-centre 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 4, R1C4 and R3C4 cannot hold 4.- Because column 5 already has a 4, R1C5 cannot hold 4.- Because row 2 already has a 4, R2C6 cannot hold 4.So 4 must go in R1C6.
  18. R6C5 = 7 · Hidden SingleIn the centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 7, R4C4 and R4C6 cannot hold 7.- Because row 5 already has a 7, R5C5 cannot hold 7.So 7 must go in R6C5.
  19. R5C7 = 4 · Hidden SingleIn the middle-right 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 4, R4C7, R4C8 and R4C9 cannot hold 4.- Because row 6 already has a 4, R6C7 and R6C9 cannot hold 4.So 4 must go in R5C7.
  20. R5C5 = 6 · Naked SingleLooking at R5C5:- Row 5 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  21. R3C9 = 4 · Hidden SingleIn the top-right 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 4, R1C9 cannot hold 4.- Because row 2 already has a 4, R2C7 cannot hold 4.- Because column 7 already has a 4, R3C7 cannot hold 4.So 4 must go in R3C9.
  22. R4C7 = 5 · Hidden SingleIn the middle-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 5, R4C8 cannot hold 5.- Because column 9 already has a 5, R4C9 cannot hold 5.- Because row 6 already has a 5, R6C7 and R6C9 cannot hold 5.So 5 must go in R4C7.
  23. R4C9 = 2 · Hidden SingleIn the middle-right 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 2, R4C8 cannot hold 2.- Because row 6 already has a 2, R6C7 and R6C9 cannot hold 2.So 2 must go in R4C9.
  24. R4C8 = 6 · Hidden SingleIn the middle-right 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because row 6 already has a 6, R6C7 and R6C9 cannot hold 6.So 6 must go in R4C8.
  25. R9C8 = 9 · Naked SingleLooking at R9C8:- Row 9 already has 3, 4 and 8 → ruled out.- Column 8 already has 1, 2, 5, 6 and 7 → ruled out.So this cell can only be 9.
  26. R7C1 = 8 · Hidden SingleIn the bottom-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because column 3 already has a 8, R8C3 cannot hold 8.- Because row 9 already has a 8, R9C1 and R9C3 cannot hold 8.So 8 must go in R7C1.
  27. R9C1 = 2 · Naked SingleLooking at R9C1:- Row 9 already has 3, 4, 8 and 9 → ruled out.- Column 1 already has 1, 5, 6 and 7 → ruled out.So this cell can only be 2.
  28. R8C3 = 9 · Hidden SingleIn the bottom-left 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 9 already has a 9, R9C3 cannot hold 9.So 9 must go in R8C3.
  29. R9C3 = 5 · Naked SingleLooking at R9C3:- Row 9 already has 2, 3, 4, 8 and 9 → ruled out.- Column 3 already has 1, 6 and 7 → ruled out.So this cell can only be 5.
  30. R8C6 = 3 · Hidden SingleIn the bottom-centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 3, R7C4 and R7C5 cannot hold 3.- Because column 4 already has a 3, R8C4 cannot hold 3.- Because column 5 already has a 3, R8C5 cannot hold 3.- Because row 9 already has a 3, R9C6 cannot hold 3.So 3 must go in R8C6.
  31. R8C5 = 5 · Hidden SingleIn the bottom-centre 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 5, R7C4 and R7C5 cannot hold 5.- Because column 4 already has a 5, R8C4 cannot hold 5.- Because row 9 already has a 5, R9C6 cannot hold 5.So 5 must go in R8C5.
  32. R8C7 = 8 · Hidden SingleIn the bottom-right 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 8, R7C7 cannot hold 8.- Because column 9 already has a 8, R8C9 cannot hold 8.- Because row 9 already has a 8, R9C7 and R9C9 cannot hold 8.So 8 must go in R8C7.
  33. R7C7 = 2 · Hidden SingleIn the bottom-right 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 2, R8C9 cannot hold 2.- Because row 9 already has a 2, R9C7 and R9C9 cannot hold 2.So 2 must go in R7C7.
  34. R8C4 = 2 · Hidden SingleIn the bottom-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 2, R7C4 and R7C5 cannot hold 2.- Because row 9 already has a 2, R9C6 cannot hold 2.So 2 must go in R8C4.
  35. R8C9 = 6 · Naked SingleLooking at R8C9:- Row 8 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  36. R9C6 = 6 · Hidden SingleIn the bottom-centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 6, R7C4 and R7C5 cannot hold 6.So 6 must go in R9C6.
  37. R3C4 = 6 · Hidden SingleIn the top-centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 6, R1C4 and R1C5 cannot hold 6.- Because column 6 already has a 6, R2C6 cannot hold 6.So 6 must go in R3C4.
  38. R3C7 = 7 · Naked SingleLooking at R3C7:- Row 3 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  39. R1C4 = 7 · Hidden SingleIn the top-centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 5 already has a 7, R1C5 cannot hold 7.- Because row 2 already has a 7, R2C6 cannot hold 7.So 7 must go in R1C4.
  40. R1C5 = 1 · Hidden SingleIn the top-centre 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 2 already has a 1, R2C6 cannot hold 1.So 1 must go in R1C5.
  41. R1C9 = 9 · Naked SingleLooking at R1C9:- Row 1 already has 1, 2, 3, 4, 5, 6, 7 and 8 → ruled out.So this cell can only be 9.
  42. R7C5 = 9 · Naked SingleLooking at R7C5:- Row 7 already has 2, 3, 4, 5, 6, 7 and 8 → ruled out.- Column 5 already has 1 → ruled out.So this cell can only be 9.
  43. R7C4 = 1 · Naked SingleLooking at R7C4:- Row 7 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  44. R4C4 = 9 · Naked SingleLooking at R4C4:- Row 4 already has 2, 3, 4, 5, 6, 7 and 8 → ruled out.- Column 4 already has 1 → ruled out.So this cell can only be 9.
  45. R4C6 = 1 · Naked SingleLooking at R4C6:- Row 4 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  46. R2C6 = 9 · Naked SingleLooking at R2C6:- Row 2 already has 1, 2, 3, 4, 5, 7 and 8 → ruled out.- Column 6 already has 6 → ruled out.So this cell can only be 9.
  47. R2C7 = 6 · Naked SingleLooking at R2C7:- Row 2 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  48. R6C7 = 9 · Hidden SingleIn the middle-right 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 9, R6C9 cannot hold 9.So 9 must go in R6C7.
  49. R6C9 = 1 · Naked SingleLooking at R6C9:- Row 6 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  50. R9C7 = 1 · Naked SingleLooking at R9C7:- Row 9 already has 2, 3, 4, 5, 6, 8 and 9 → ruled out.- Column 7 already has 7 → ruled out.So this cell can only be 1.
  51. R9C9 = 7 · Naked SingleLooking at R9C9:- Row 9 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.

First to finish

Ranked by when each player finished, not by how long they took — so looking up a solution never moves anyone up this board.

Open the app to see who finished first.

Recent days

Full archive →