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Daily Sudoku — 31 July 2026

The puzzle

  • 31 July 2026
  • Medium
  • 34 clues
Puzzle
62·7·1·8·
·58·4·7··
·1·3·5···
····57··3
·7····4··
··24··9·7
··61··5·9
59··681··
···53··68
Solution
624791385
358642791
719385642
461957823
975823416
832416957
286174539
593268174
147539268

Solve it in the app to get on the board

Step-by-step solution

Every cell below is filled by the same hint engine the app uses, in the order it can be deduced — 47 steps using 2 techniques.

Techniques used

  • Hidden Single — inside one row, column or box this digit fits in only one cell, so it must go there
  • Naked Single — every other digit is already used in this cell's row, column or box, so only one candidate is left
  1. R3C5 = 8 · Hidden SingleIn the top-centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 8, R1C5 cannot hold 8.- Because row 2 already has a 8, R2C4 and R2C6 cannot hold 8.So 8 must go in R3C5.
  2. R1C9 = 5 · Hidden SingleIn the top-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 5, R1C7 cannot hold 5.- Because row 2 already has a 5, R2C8 and R2C9 cannot hold 5.- Because row 3 already has a 5, R3C7, R3C8 and R3C9 cannot hold 5.So 5 must go in R1C9.
  3. R5C3 = 5 · Hidden SingleIn the middle-left 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 5, R4C1, R4C2 and R4C3 cannot hold 5.- Because column 1 already has a 5, R5C1 and R6C1 cannot hold 5.- Because column 2 already has a 5, R6C2 cannot hold 5.So 5 must go in R5C3.
  4. R6C8 = 5 · Hidden SingleIn the middle-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 5, R4C7 and R4C8 cannot hold 5.- Because row 5 already has a 5, R5C8 and R5C9 cannot hold 5.So 5 must go in R6C8.
  5. R4C7 = 8 · Hidden SingleIn the middle-right 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 8, R4C8 and R5C8 cannot hold 8.- Because column 9 already has a 8, R5C9 cannot hold 8.So 8 must go in R4C7.
  6. R5C4 = 8 · Hidden SingleIn the centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 8, R4C4 cannot hold 8.- Because column 5 already has a 8, R5C5 and R6C5 cannot hold 8.- Because column 6 already has a 8, R5C6 and R6C6 cannot hold 8.So 8 must go in R5C4.
  7. R5C9 = 6 · Hidden SingleIn the middle-right 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 6, R4C8 and R5C8 cannot hold 6.So 6 must go in R5C9.
  8. R3C7 = 6 · Hidden SingleIn the top-right 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 6, R1C7 cannot hold 6.- Because column 8 already has a 6, R2C8 and R3C8 cannot hold 6.- Because column 9 already has a 6, R2C9 and R3C9 cannot hold 6.So 6 must go in R3C7.
  9. R7C5 = 7 · Hidden SingleIn the bottom-centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 6 already has a 7, R7C6 and R9C6 cannot hold 7.- Because column 4 already has a 7, R8C4 cannot hold 7.So 7 must go in R7C5.
  10. R9C6 = 9 · Hidden SingleIn the bottom-centre 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 9, R7C6 cannot hold 9.- Because row 8 already has a 9, R8C4 cannot hold 9.So 9 must go in R9C6.
  11. R7C6 = 4 · Hidden SingleIn the bottom-centre 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 4, R8C4 cannot hold 4.So 4 must go in R7C6.
  12. R8C4 = 2 · Naked SingleLooking at R8C4:- Row 8 already has 1, 5, 6, 8 and 9 → ruled out.- Column 4 already has 3, 4 and 7 → ruled out.So this cell can only be 2.
  13. R2C6 = 2 · Hidden SingleIn the top-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 2, R1C5 cannot hold 2.- Because column 4 already has a 2, R2C4 cannot hold 2.So 2 must go in R2C6.
  14. R2C4 = 6 · Hidden SingleIn the top-centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 6, R1C5 cannot hold 6.So 6 must go in R2C4.
  15. R4C4 = 9 · Naked SingleLooking at R4C4:- Row 4 already has 3, 5, 7 and 8 → ruled out.- Column 4 already has 1, 2, 4 and 6 → ruled out.So this cell can only be 9.
  16. R1C5 = 9 · Naked SingleLooking at R1C5:- Row 1 already has 1, 2, 5, 6, 7 and 8 → ruled out.- Column 5 already has 3 and 4 → ruled out.So this cell can only be 9.
  17. R5C1 = 9 · Hidden SingleIn the middle-left 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 9, R4C1, R4C2 and R4C3 cannot hold 9.- Because row 6 already has a 9, R6C1 and R6C2 cannot hold 9.So 9 must go in R5C1.
  18. R3C3 = 9 · Hidden SingleIn the top-left 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 9, R1C3 cannot hold 9.- Because column 1 already has a 9, R2C1 and R3C1 cannot hold 9.So 9 must go in R3C3.
  19. R3C1 = 7 · Hidden SingleIn the top-left 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 7, R1C3 cannot hold 7.- Because row 2 already has a 7, R2C1 cannot hold 7.So 7 must go in R3C1.
  20. R1C3 = 4 · Hidden SingleIn the top-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 2 already has a 4, R2C1 cannot hold 4.So 4 must go in R1C3.
  21. R1C7 = 3 · Naked SingleLooking at R1C7:- Row 1 already has 1, 2, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 3.
  22. R9C7 = 2 · Naked SingleLooking at R9C7:- Row 9 already has 3, 5, 6, 8 and 9 → ruled out.- Column 7 already has 1, 4 and 7 → ruled out.So this cell can only be 2.
  23. R2C1 = 3 · Naked SingleLooking at R2C1:- Row 2 already has 2, 4, 5, 6, 7 and 8 → ruled out.- Column 1 already has 9 → ruled out.- The top-left 3×3 box already has 1 → ruled out.So this cell can only be 3.
  24. R2C8 = 9 · Hidden SingleIn the top-right 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 9, R2C9 cannot hold 9.- Because row 3 already has a 9, R3C8 and R3C9 cannot hold 9.So 9 must go in R2C8.
  25. R2C9 = 1 · Naked SingleLooking at R2C9:- Row 2 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  26. R6C2 = 3 · Hidden SingleIn the middle-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 3, R4C1, R4C2 and R4C3 cannot hold 3.- Because column 1 already has a 3, R6C1 cannot hold 3.So 3 must go in R6C2.
  27. R4C2 = 6 · Hidden SingleIn the middle-left 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 6, R4C1 and R6C1 cannot hold 6.- Because column 3 already has a 6, R4C3 cannot hold 6.So 6 must go in R4C2.
  28. R4C1 = 4 · Hidden SingleIn the middle-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 3 already has a 4, R4C3 cannot hold 4.- Because row 6 already has a 4, R6C1 cannot hold 4.So 4 must go in R4C1.
  29. R6C1 = 8 · Hidden SingleIn the middle-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 8, R4C3 cannot hold 8.So 8 must go in R6C1.
  30. R4C3 = 1 · Naked SingleLooking at R4C3:- Row 4 already has 3, 4, 5, 6, 7, 8 and 9 → ruled out.- Column 3 already has 2 → ruled out.So this cell can only be 1.
  31. R4C8 = 2 · Naked SingleLooking at R4C8:- Row 4 already has 1, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 2.
  32. R5C8 = 1 · Naked SingleLooking at R5C8:- Row 5 already has 4, 5, 6, 7, 8 and 9 → ruled out.- Column 8 already has 2 → ruled out.- The middle-right 3×3 box already has 3 → ruled out.So this cell can only be 1.
  33. R3C9 = 2 · Hidden SingleIn the top-right 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 2, R3C8 cannot hold 2.So 2 must go in R3C9.
  34. R3C8 = 4 · Naked SingleLooking at R3C8:- Row 3 already has 1, 2, 3, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 4.
  35. R8C9 = 4 · Naked SingleLooking at R8C9:- Row 8 already has 1, 2, 5, 6, 8 and 9 → ruled out.- Column 9 already has 3 and 7 → ruled out.So this cell can only be 4.
  36. R6C5 = 1 · Hidden SingleIn the centre 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 5 already has a 1, R5C5 and R5C6 cannot hold 1.- Because column 6 already has a 1, R6C6 cannot hold 1.So 1 must go in R6C5.
  37. R6C6 = 6 · Naked SingleLooking at R6C6:- Row 6 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  38. R5C5 = 2 · Naked SingleLooking at R5C5:- Row 5 already has 1, 4, 5, 6, 7, 8 and 9 → ruled out.- Column 5 already has 3 → ruled out.So this cell can only be 2.
  39. R5C6 = 3 · Naked SingleLooking at R5C6:- Row 5 already has 1, 2, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 3.
  40. R9C1 = 1 · Hidden SingleIn the bottom-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 1, R7C1 and R7C2 cannot hold 1.- Because row 8 already has a 1, R8C3 cannot hold 1.- Because column 2 already has a 1, R9C2 cannot hold 1.- Because column 3 already has a 1, R9C3 cannot hold 1.So 1 must go in R9C1.
  41. R7C1 = 2 · Naked SingleLooking at R7C1:- Row 7 already has 1, 4, 5, 6, 7 and 9 → ruled out.- Column 1 already has 3 and 8 → ruled out.So this cell can only be 2.
  42. R8C3 = 3 · Hidden SingleIn the bottom-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 2 already has a 3, R7C2 cannot hold 3.- Because row 9 already has a 3, R9C2 and R9C3 cannot hold 3.So 3 must go in R8C3.
  43. R8C8 = 7 · Naked SingleLooking at R8C8:- Row 8 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  44. R9C3 = 7 · Naked SingleLooking at R9C3:- Row 9 already has 1, 2, 3, 5, 6, 8 and 9 → ruled out.- Column 3 already has 4 → ruled out.So this cell can only be 7.
  45. R9C2 = 4 · Naked SingleLooking at R9C2:- Row 9 already has 1, 2, 3, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 4.
  46. R7C2 = 8 · Naked SingleLooking at R7C2:- Row 7 already has 1, 2, 4, 5, 6, 7 and 9 → ruled out.- Column 2 already has 3 → ruled out.So this cell can only be 8.
  47. R7C8 = 3 · Naked SingleLooking at R7C8:- Row 7 already has 1, 2, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 3.

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