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Daily Sudoku — 21 July 2026

The puzzle

  • 21 July 2026
  • Easy
  • 40 clues
Puzzle
···9·5·2·
·2···64··
459·82··3
·7·514··2
382·9·14·
··52·89··
6·875·214
2····3597
·······3·
Solution
763945821
821376459
459182763
976514382
382697145
145238976
638759214
214863597
597421638

Solve it in the app to get on the board

Step-by-step solution

Every cell below is filled by the same hint engine the app uses, in the order it can be deduced — 41 steps using 2 techniques.

Techniques used

  • Hidden Single — inside one row, column or box this digit fits in only one cell, so it must go there
  • Naked Single — every other digit is already used in this cell's row, column or box, so only one candidate is left
  1. R1C5 = 4 · Hidden SingleIn the top-centre 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 2 already has a 4, R2C4 and R2C5 cannot hold 4.- Because row 3 already has a 4, R3C4 cannot hold 4.So 4 must go in R1C5.
  2. R2C5 = 7 · Hidden SingleIn the top-centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 7, R2C4 and R3C4 cannot hold 7.So 7 must go in R2C5.
  3. R2C4 = 3 · Hidden SingleIn the top-centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 3 already has a 3, R3C4 cannot hold 3.So 3 must go in R2C4.
  4. R3C4 = 1 · Naked SingleLooking at R3C4:- Row 3 already has 2, 3, 4, 5, 8 and 9 → ruled out.- Column 4 already has 7 → ruled out.- The top-centre 3×3 box already has 6 → ruled out.So this cell can only be 1.
  5. R2C9 = 9 · Hidden SingleIn the top-right 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 9, R1C7 and R1C9 cannot hold 9.- Because column 8 already has a 9, R2C8 cannot hold 9.- Because row 3 already has a 9, R3C7 and R3C8 cannot hold 9.So 9 must go in R2C9.
  6. R1C9 = 1 · Hidden SingleIn the top-right 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 1, R1C7 cannot hold 1.- Because column 8 already has a 1, R2C8 cannot hold 1.- Because row 3 already has a 1, R3C7 and R3C8 cannot hold 1.So 1 must go in R1C9.
  7. R2C8 = 5 · Hidden SingleIn the top-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 5, R1C7 cannot hold 5.- Because row 3 already has a 5, R3C7 and R3C8 cannot hold 5.So 5 must go in R2C8.
  8. R1C7 = 8 · Hidden SingleIn the top-right 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 3 already has a 8, R3C7 and R3C8 cannot hold 8.So 8 must go in R1C7.
  9. R2C1 = 8 · Hidden SingleIn the top-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 8, R1C1, R1C2 and R1C3 cannot hold 8.- Because column 3 already has a 8, R2C3 cannot hold 8.So 8 must go in R2C1.
  10. R2C3 = 1 · Naked SingleLooking at R2C3:- Row 2 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  11. R6C2 = 4 · Hidden SingleIn the middle-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 4, R4C1 and R4C3 cannot hold 4.- Because column 1 already has a 4, R6C1 cannot hold 4.So 4 must go in R6C2.
  12. R6C1 = 1 · Hidden SingleIn the middle-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 1, R4C1 and R4C3 cannot hold 1.So 1 must go in R6C1.
  13. R4C3 = 6 · Hidden SingleIn the middle-left 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 6, R4C1 cannot hold 6.So 6 must go in R4C3.
  14. R4C1 = 9 · Naked SingleLooking at R4C1:- Row 4 already has 1, 2, 4, 5, 6 and 7 → ruled out.- Column 1 already has 3 and 8 → ruled out.So this cell can only be 9.
  15. R1C2 = 6 · Hidden SingleIn the top-left 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 6, R1C1 cannot hold 6.- Because column 3 already has a 6, R1C3 cannot hold 6.So 6 must go in R1C2.
  16. R1C3 = 3 · Hidden SingleIn the top-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 3, R1C1 cannot hold 3.So 3 must go in R1C3.
  17. R1C1 = 7 · Naked SingleLooking at R1C1:- Row 1 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  18. R9C1 = 5 · Naked SingleLooking at R9C1:- Row 9 already has 3 → ruled out.- Column 1 already has 1, 2, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.
  19. R6C5 = 3 · Hidden SingleIn the centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 5 already has a 3, R5C4 and R5C6 cannot hold 3.So 3 must go in R6C5.
  20. R5C4 = 6 · Hidden SingleIn the centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 6 already has a 6, R5C6 cannot hold 6.So 6 must go in R5C4.
  21. R5C6 = 7 · Naked SingleLooking at R5C6:- Row 5 already has 1, 2, 3, 4, 6, 8 and 9 → ruled out.- Column 6 already has 5 → ruled out.So this cell can only be 7.
  22. R5C9 = 5 · Naked SingleLooking at R5C9:- Row 5 already has 1, 2, 3, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.
  23. R4C7 = 3 · Hidden SingleIn the middle-right 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 3, R4C8 cannot hold 3.- Because row 6 already has a 3, R6C8 and R6C9 cannot hold 3.So 3 must go in R4C7.
  24. R4C8 = 8 · Naked SingleLooking at R4C8:- Row 4 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.
  25. R6C8 = 7 · Hidden SingleIn the middle-right 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 7, R6C9 cannot hold 7.So 7 must go in R6C8.
  26. R6C9 = 6 · Naked SingleLooking at R6C9:- Row 6 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  27. R3C8 = 6 · Naked SingleLooking at R3C8:- Row 3 already has 1, 2, 3, 4, 5, 8 and 9 → ruled out.- Column 8 already has 7 → ruled out.So this cell can only be 6.
  28. R3C7 = 7 · Naked SingleLooking at R3C7:- Row 3 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  29. R9C7 = 6 · Naked SingleLooking at R9C7:- Row 9 already has 3 and 5 → ruled out.- Column 7 already has 1, 2, 4, 7, 8 and 9 → ruled out.So this cell can only be 6.
  30. R9C9 = 8 · Naked SingleLooking at R9C9:- Row 9 already has 3, 5 and 6 → ruled out.- Column 9 already has 1, 2, 4, 7 and 9 → ruled out.So this cell can only be 8.
  31. R7C2 = 3 · Hidden SingleIn the bottom-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 3, R8C2 and R8C3 cannot hold 3.- Because row 9 already has a 3, R9C2 and R9C3 cannot hold 3.So 3 must go in R7C2.
  32. R7C6 = 9 · Naked SingleLooking at R7C6:- Row 7 already has 1, 2, 3, 4, 5, 6, 7 and 8 → ruled out.So this cell can only be 9.
  33. R9C6 = 1 · Naked SingleLooking at R9C6:- Row 9 already has 3, 5, 6 and 8 → ruled out.- Column 6 already has 2, 4, 7 and 9 → ruled out.So this cell can only be 1.
  34. R8C2 = 1 · Hidden SingleIn the bottom-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because column 3 already has a 1, R8C3 cannot hold 1.- Because row 9 already has a 1, R9C2 and R9C3 cannot hold 1.So 1 must go in R8C2.
  35. R9C2 = 9 · Naked SingleLooking at R9C2:- Row 9 already has 1, 3, 5, 6 and 8 → ruled out.- Column 2 already has 2, 4 and 7 → ruled out.So this cell can only be 9.
  36. R9C3 = 7 · Hidden SingleIn the bottom-left 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 7, R8C3 cannot hold 7.So 7 must go in R9C3.
  37. R8C3 = 4 · Naked SingleLooking at R8C3:- Row 8 already has 1, 2, 3, 5, 7 and 9 → ruled out.- Column 3 already has 6 and 8 → ruled out.So this cell can only be 4.
  38. R9C5 = 2 · Hidden SingleIn the bottom-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 2, R8C4 and R8C5 cannot hold 2.- Because column 4 already has a 2, R9C4 cannot hold 2.So 2 must go in R9C5.
  39. R9C4 = 4 · Naked SingleLooking at R9C4:- Row 9 already has 1, 2, 3, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 4.
  40. R8C4 = 8 · Naked SingleLooking at R8C4:- Row 8 already has 1, 2, 3, 4, 5, 7 and 9 → ruled out.- Column 4 already has 6 → ruled out.So this cell can only be 8.
  41. R8C5 = 6 · Naked SingleLooking at R8C5:- Row 8 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.

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