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Daily Sudoku — 1 July 2026

The puzzle

  • 1 July 2026
  • Easy
  • 40 clues
Puzzle
9·5·8···2
····1435·
2·4·358·6
·6·72·9··
7·8·9··35
·9156·2·7
159······
8···5··63
3·6·4··9·
Solution
935687142
687214359
214935876
563728914
728491635
491563287
159376428
842159763
376842591

Solve it in the app to get on the board

Step-by-step solution

Every cell below is filled by the same hint engine the app uses, in the order it can be deduced — 41 steps using 2 techniques.

Techniques used

  • Naked Single — every other digit is already used in this cell's row, column or box, so only one candidate is left
  • Hidden Single — inside one row, column or box this digit fits in only one cell, so it must go there
  1. R7C5 = 7 · Naked SingleLooking at R7C5:- Row 7 already has 1, 5 and 9 → ruled out.- Column 5 already has 2, 3, 4, 6 and 8 → ruled out.So this cell can only be 7.
  2. R1C2 = 3 · Hidden SingleIn the top-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 2 already has a 3, R2C1, R2C2 and R2C3 cannot hold 3.- Because row 3 already has a 3, R3C2 cannot hold 3.So 3 must go in R1C2.
  3. R3C2 = 1 · Hidden SingleIn the top-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 2 already has a 1, R2C1, R2C2 and R2C3 cannot hold 1.So 1 must go in R3C2.
  4. R2C1 = 6 · Hidden SingleIn the top-left 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 2 already has a 6, R2C2 cannot hold 6.- Because column 3 already has a 6, R2C3 cannot hold 6.So 6 must go in R2C1.
  5. R2C2 = 8 · Hidden SingleIn the top-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because column 3 already has a 8, R2C3 cannot hold 8.So 8 must go in R2C2.
  6. R2C3 = 7 · Naked SingleLooking at R2C3:- Row 2 already has 1, 3, 4, 5, 6 and 8 → ruled out.- Column 3 already has 9 → ruled out.- The top-left 3×3 box already has 2 → ruled out.So this cell can only be 7.
  7. R2C4 = 2 · Hidden SingleIn the top-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 2, R1C4 and R1C6 cannot hold 2.- Because row 3 already has a 2, R3C4 cannot hold 2.So 2 must go in R2C4.
  8. R2C9 = 9 · Naked SingleLooking at R2C9:- Row 2 already has 1, 2, 3, 4, 5, 6, 7 and 8 → ruled out.So this cell can only be 9.
  9. R1C6 = 7 · Hidden SingleIn the top-centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 7, R1C4 and R3C4 cannot hold 7.So 7 must go in R1C6.
  10. R1C4 = 6 · Hidden SingleIn the top-centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because row 3 already has a 6, R3C4 cannot hold 6.So 6 must go in R1C4.
  11. R3C4 = 9 · Naked SingleLooking at R3C4:- Row 3 already has 1, 2, 3, 4, 5, 6 and 8 → ruled out.- Column 4 already has 7 → ruled out.So this cell can only be 9.
  12. R3C8 = 7 · Naked SingleLooking at R3C8:- Row 3 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  13. R5C2 = 2 · Hidden SingleIn the middle-left 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 2, R4C1 and R4C3 cannot hold 2.- Because row 6 already has a 2, R6C1 cannot hold 2.So 2 must go in R5C2.
  14. R4C3 = 3 · Hidden SingleIn the middle-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 3, R4C1 and R6C1 cannot hold 3.So 3 must go in R4C3.
  15. R8C3 = 2 · Naked SingleLooking at R8C3:- Row 8 already has 3, 5, 6 and 8 → ruled out.- Column 3 already has 1, 4, 7 and 9 → ruled out.So this cell can only be 2.
  16. R4C1 = 5 · Hidden SingleIn the middle-left 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 6 already has a 5, R6C1 cannot hold 5.So 5 must go in R4C1.
  17. R6C1 = 4 · Naked SingleLooking at R6C1:- Row 6 already has 1, 2, 5, 6, 7 and 9 → ruled out.- Column 1 already has 3 and 8 → ruled out.So this cell can only be 4.
  18. R6C6 = 3 · Hidden SingleIn the centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 3, R4C6 cannot hold 3.- Because row 5 already has a 3, R5C4 and R5C6 cannot hold 3.So 3 must go in R6C6.
  19. R6C8 = 8 · Naked SingleLooking at R6C8:- Row 6 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.
  20. R5C4 = 4 · Hidden SingleIn the centre 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 6 already has a 4, R4C6 and R5C6 cannot hold 4.So 4 must go in R5C4.
  21. R4C6 = 8 · Hidden SingleIn the centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 5 already has a 8, R5C6 cannot hold 8.So 8 must go in R4C6.
  22. R5C6 = 1 · Naked SingleLooking at R5C6:- Row 5 already has 2, 3, 4, 5, 7, 8 and 9 → ruled out.- The centre 3×3 box already has 6 → ruled out.So this cell can only be 1.
  23. R5C7 = 6 · Naked SingleLooking at R5C7:- Row 5 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  24. R8C2 = 4 · Hidden SingleIn the bottom-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 9 already has a 4, R9C2 cannot hold 4.So 4 must go in R8C2.
  25. R9C2 = 7 · Naked SingleLooking at R9C2:- Row 9 already has 3, 4, 6 and 9 → ruled out.- Column 2 already has 1, 2, 5 and 8 → ruled out.So this cell can only be 7.
  26. R7C4 = 3 · Hidden SingleIn the bottom-centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 6 already has a 3, R7C6 cannot hold 3.- Because row 8 already has a 3, R8C4 and R8C6 cannot hold 3.- Because row 9 already has a 3, R9C4 and R9C6 cannot hold 3.So 3 must go in R7C4.
  27. R7C6 = 6 · Hidden SingleIn the bottom-centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 6, R8C4 and R8C6 cannot hold 6.- Because row 9 already has a 6, R9C4 and R9C6 cannot hold 6.So 6 must go in R7C6.
  28. R9C6 = 2 · Hidden SingleIn the bottom-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 2, R8C4 and R8C6 cannot hold 2.- Because column 4 already has a 2, R9C4 cannot hold 2.So 2 must go in R9C6.
  29. R8C6 = 9 · Naked SingleLooking at R8C6:- Row 8 already has 2, 3, 4, 5, 6 and 8 → ruled out.- Column 6 already has 1 and 7 → ruled out.So this cell can only be 9.
  30. R9C4 = 8 · Hidden SingleIn the bottom-centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 8, R8C4 cannot hold 8.So 8 must go in R9C4.
  31. R8C4 = 1 · Naked SingleLooking at R8C4:- Row 8 already has 2, 3, 4, 5, 6, 8 and 9 → ruled out.- Column 4 already has 7 → ruled out.So this cell can only be 1.
  32. R8C7 = 7 · Naked SingleLooking at R8C7:- Row 8 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  33. R7C8 = 2 · Hidden SingleIn the bottom-right 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 2, R7C7 cannot hold 2.- Because column 9 already has a 2, R7C9 cannot hold 2.- Because row 9 already has a 2, R9C7 and R9C9 cannot hold 2.So 2 must go in R7C8.
  34. R9C7 = 5 · Hidden SingleIn the bottom-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 5, R7C7 and R7C9 cannot hold 5.- Because column 9 already has a 5, R9C9 cannot hold 5.So 5 must go in R9C7.
  35. R9C9 = 1 · Naked SingleLooking at R9C9:- Row 9 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  36. R4C8 = 1 · Hidden SingleIn the middle-right 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 1, R4C9 cannot hold 1.So 1 must go in R4C8.
  37. R4C9 = 4 · Naked SingleLooking at R4C9:- Row 4 already has 1, 2, 3, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 4.
  38. R1C8 = 4 · Naked SingleLooking at R1C8:- Row 1 already has 2, 3, 5, 6, 7, 8 and 9 → ruled out.- Column 8 already has 1 → ruled out.So this cell can only be 4.
  39. R1C7 = 1 · Naked SingleLooking at R1C7:- Row 1 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  40. R7C7 = 4 · Naked SingleLooking at R7C7:- Row 7 already has 1, 2, 3, 5, 6, 7 and 9 → ruled out.- Column 7 already has 8 → ruled out.So this cell can only be 4.
  41. R7C9 = 8 · Naked SingleLooking at R7C9:- Row 7 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.

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