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Daily Sudoku — 22 September 2026

The puzzle

  • 22 September 2026
  • Medium
  • 34 clues
Puzzle
·6····9··
··2·6···8
··7··945·
·2·15·3·7
·5·9·3···
··9·2·8·5
5483·····
7·3·9·5·4
29·····31
Solution
465781923
932564178
187239456
624158397
851973642
379426815
548317269
713692584
296845731

Solve it in the app to get on the board

Step-by-step solution

Every cell below is filled by the same hint engine the app uses, in the order it can be deduced — 47 steps using 2 techniques.

Techniques used

  • Hidden Single — inside one row, column or box this digit fits in only one cell, so it must go there
  • Naked Single — every other digit is already used in this cell's row, column or box, so only one candidate is left
  1. R1C3 = 5 · Hidden SingleIn the top-left 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 5, R1C1 and R2C1 cannot hold 5.- Because column 2 already has a 5, R2C2 cannot hold 5.- Because row 3 already has a 5, R3C1 and R3C2 cannot hold 5.So 5 must go in R1C3.
  2. R2C1 = 9 · Hidden SingleIn the top-left 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 9, R1C1 cannot hold 9.- Because column 2 already has a 9, R2C2 cannot hold 9.- Because row 3 already has a 9, R3C1 and R3C2 cannot hold 9.So 9 must go in R2C1.
  3. R1C1 = 4 · Hidden SingleIn the top-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 2 already has a 4, R2C2 cannot hold 4.- Because row 3 already has a 4, R3C1 and R3C2 cannot hold 4.So 4 must go in R1C1.
  4. R3C9 = 6 · Hidden SingleIn the top-right 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 6, R1C8 and R1C9 cannot hold 6.- Because row 2 already has a 6, R2C7 and R2C8 cannot hold 6.So 6 must go in R3C9.
  5. R1C9 = 3 · Hidden SingleIn the top-right 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 3, R1C8 and R2C8 cannot hold 3.- Because column 7 already has a 3, R2C7 cannot hold 3.So 3 must go in R1C9.
  6. R3C5 = 3 · Hidden SingleIn the top-centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 3, R1C4, R1C5 and R1C6 cannot hold 3.- Because column 4 already has a 3, R2C4 and R3C4 cannot hold 3.- Because column 6 already has a 3, R2C6 cannot hold 3.So 3 must go in R3C5.
  7. R2C2 = 3 · Hidden SingleIn the top-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 3 already has a 3, R3C1 and R3C2 cannot hold 3.So 3 must go in R2C2.
  8. R1C8 = 2 · Hidden SingleIn the top-right 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 2 already has a 2, R2C7 and R2C8 cannot hold 2.So 2 must go in R1C8.
  9. R3C4 = 2 · Hidden SingleIn the top-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 2, R1C4, R1C5 and R1C6 cannot hold 2.- Because row 2 already has a 2, R2C4 and R2C6 cannot hold 2.So 2 must go in R3C4.
  10. R6C1 = 3 · Hidden SingleIn the middle-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 3, R4C1 and R4C3 cannot hold 3.- Because row 5 already has a 3, R5C1 and R5C3 cannot hold 3.- Because column 2 already has a 3, R6C2 cannot hold 3.So 3 must go in R6C1.
  11. R6C2 = 7 · Hidden SingleIn the middle-left 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 7, R4C1 and R4C3 cannot hold 7.- Because column 1 already has a 7, R5C1 cannot hold 7.- Because column 3 already has a 7, R5C3 cannot hold 7.So 7 must go in R6C2.
  12. R5C5 = 7 · Hidden SingleIn the centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 7, R4C6 cannot hold 7.- Because row 6 already has a 7, R6C4 and R6C6 cannot hold 7.So 7 must go in R5C5.
  13. R4C6 = 8 · Hidden SingleIn the centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 6 already has an 8, R6C4 and R6C6 cannot hold 8.So 8 must go in R4C6.
  14. R5C1 = 8 · Hidden SingleIn the middle-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 4 already has an 8, R4C1 and R4C3 cannot hold 8.- Because column 3 already has an 8, R5C3 cannot hold 8.So 8 must go in R5C1.
  15. R3C2 = 8 · Hidden SingleIn the top-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because column 1 already has an 8, R3C1 cannot hold 8.So 8 must go in R3C2.
  16. R3C1 = 1 · Naked SingleLooking at R3C1:- Row 3 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  17. R4C1 = 6 · Naked SingleLooking at R4C1:- Row 4 already has 1, 2, 3, 5, 7 and 8 → ruled out.- Column 1 already has 4 and 9 → ruled out.So this cell can only be 6.
  18. R8C2 = 1 · Naked SingleLooking at R8C2:- Row 8 already has 3, 4, 5, 7 and 9 → ruled out.- Column 2 already has 2, 6 and 8 → ruled out.So this cell can only be 1.
  19. R9C3 = 6 · Naked SingleLooking at R9C3:- Row 9 already has 1, 2, 3 and 9 → ruled out.- Column 3 already has 5, 7 and 8 → ruled out.- The bottom-left 3×3 box already has 4 → ruled out.So this cell can only be 6.
  20. R5C3 = 1 · Hidden SingleIn the middle-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 1, R4C3 cannot hold 1.So 1 must go in R5C3.
  21. R4C3 = 4 · Naked SingleLooking at R4C3:- Row 4 already has 1, 2, 3, 5, 6, 7 and 8 → ruled out.- Column 3 already has 9 → ruled out.So this cell can only be 4.
  22. R4C8 = 9 · Naked SingleLooking at R4C8:- Row 4 already has 1, 2, 3, 4, 5, 6, 7 and 8 → ruled out.So this cell can only be 9.
  23. R6C8 = 1 · Hidden SingleIn the middle-right 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 5 already has a 1, R5C7, R5C8 and R5C9 cannot hold 1.So 1 must go in R6C8.
  24. R2C7 = 1 · Hidden SingleIn the top-right 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 1, R2C8 cannot hold 1.So 1 must go in R2C7.
  25. R2C8 = 7 · Naked SingleLooking at R2C8:- Row 2 already has 1, 2, 3, 6, 8 and 9 → ruled out.- Column 8 already has 5 → ruled out.- The top-right 3×3 box already has 4 → ruled out.So this cell can only be 7.
  26. R5C8 = 4 · Hidden SingleIn the middle-right 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 4, R5C7 cannot hold 4.- Because column 9 already has a 4, R5C9 cannot hold 4.So 4 must go in R5C8.
  27. R5C7 = 6 · Hidden SingleIn the middle-right 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 6, R5C9 cannot hold 6.So 6 must go in R5C7.
  28. R5C9 = 2 · Naked SingleLooking at R5C9:- Row 5 already has 1, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 2.
  29. R7C9 = 9 · Naked SingleLooking at R7C9:- Row 7 already has 3, 4, 5 and 8 → ruled out.- Column 9 already has 1, 2, 6 and 7 → ruled out.So this cell can only be 9.
  30. R7C7 = 2 · Hidden SingleIn the bottom-right 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 2, R7C8 and R8C8 cannot hold 2.- Because row 9 already has a 2, R9C7 cannot hold 2.So 2 must go in R7C7.
  31. R9C7 = 7 · Naked SingleLooking at R9C7:- Row 9 already has 1, 2, 3, 6 and 9 → ruled out.- Column 7 already has 4, 5 and 8 → ruled out.So this cell can only be 7.
  32. R8C6 = 2 · Hidden SingleIn the bottom-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 2, R7C5 and R7C6 cannot hold 2.- Because column 4 already has a 2, R8C4 cannot hold 2.- Because row 9 already has a 2, R9C4, R9C5 and R9C6 cannot hold 2.So 2 must go in R8C6.
  33. R7C6 = 7 · Hidden SingleIn the bottom-centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 5 already has a 7, R7C5 cannot hold 7.- Because row 8 already has a 7, R8C4 cannot hold 7.- Because row 9 already has a 7, R9C4, R9C5 and R9C6 cannot hold 7.So 7 must go in R7C6.
  34. R1C4 = 7 · Hidden SingleIn the top-centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 5 already has a 7, R1C5 cannot hold 7.- Because column 6 already has a 7, R1C6 cannot hold 7.- Because row 2 already has a 7, R2C4 and R2C6 cannot hold 7.So 7 must go in R1C4.
  35. R1C5 = 8 · Hidden SingleIn the top-centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because column 6 already has an 8, R1C6 cannot hold 8.- Because row 2 already has an 8, R2C4 and R2C6 cannot hold 8.So 8 must go in R1C5.
  36. R1C6 = 1 · Naked SingleLooking at R1C6:- Row 1 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  37. R7C5 = 1 · Hidden SingleIn the bottom-centre 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 1, R8C4 cannot hold 1.- Because row 9 already has a 1, R9C4, R9C5 and R9C6 cannot hold 1.So 1 must go in R7C5.
  38. R7C8 = 6 · Naked SingleLooking at R7C8:- Row 7 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  39. R9C5 = 4 · Naked SingleLooking at R9C5:- Row 9 already has 1, 2, 3, 6, 7 and 9 → ruled out.- Column 5 already has 5 and 8 → ruled out.So this cell can only be 4.
  40. R8C8 = 8 · Naked SingleLooking at R8C8:- Row 8 already has 1, 2, 3, 4, 5, 7 and 9 → ruled out.- Column 8 already has 6 → ruled out.So this cell can only be 8.
  41. R8C4 = 6 · Naked SingleLooking at R8C4:- Row 8 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  42. R6C6 = 6 · Hidden SingleIn the centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 6, R6C4 cannot hold 6.So 6 must go in R6C6.
  43. R6C4 = 4 · Naked SingleLooking at R6C4:- Row 6 already has 1, 2, 3, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 4.
  44. R2C6 = 4 · Hidden SingleIn the top-centre 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 4, R2C4 cannot hold 4.So 4 must go in R2C6.
  45. R2C4 = 5 · Naked SingleLooking at R2C4:- Row 2 already has 1, 2, 3, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.
  46. R9C4 = 8 · Naked SingleLooking at R9C4:- Row 9 already has 1, 2, 3, 4, 6, 7 and 9 → ruled out.- Column 4 already has 5 → ruled out.So this cell can only be 8.
  47. R9C6 = 5 · Naked SingleLooking at R9C6:- Row 9 already has 1, 2, 3, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.

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