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Daily Sudoku — 3 October 2026

The puzzle

  • 3 October 2026
  • Medium
  • 34 clues
Puzzle
165······
23··4716·
94··6····
72···4·1·
·9481·72·
·····3··4
4········
···472··9
·5·3·1·72
Solution
165238947
238947165
947165238
723594816
594816723
816723594
472659381
381472659
659381472

Solve it in the app to get on the board

Step-by-step solution

Every cell below is filled by the same hint engine the app uses, in the order it can be deduced — 47 steps using 2 techniques.

Techniques used

  • Hidden Single — inside one row, column or box this digit fits in only one cell, so it must go there
  • Naked Single — every other digit is already used in this cell's row, column or box, so only one candidate is left
  1. R3C3 = 7 · Hidden SingleIn the top-left 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 2 already has a 7, R2C3 cannot hold 7.So 7 must go in R3C3.
  2. R2C3 = 8 · Naked SingleLooking at R2C3:- Row 2 already has 1, 2, 3, 4, 6 and 7 → ruled out.- Column 3 already has 5 → ruled out.- The top-left 3×3 box already has 9 → ruled out.So this cell can only be 8.
  3. R3C4 = 1 · Hidden SingleIn the top-centre 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 1, R1C4, R1C5 and R1C6 cannot hold 1.- Because row 2 already has a 1, R2C4 cannot hold 1.- Because column 6 already has a 1, R3C6 cannot hold 1.So 1 must go in R3C4.
  4. R1C5 = 3 · Hidden SingleIn the top-centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 3, R1C4 cannot hold 3.- Because column 6 already has a 3, R1C6 and R3C6 cannot hold 3.- Because row 2 already has a 3, R2C4 cannot hold 3.So 3 must go in R1C5.
  5. R1C4 = 2 · Hidden SingleIn the top-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 6 already has a 2, R1C6 and R3C6 cannot hold 2.- Because row 2 already has a 2, R2C4 cannot hold 2.So 2 must go in R1C4.
  6. R3C7 = 2 · Hidden SingleIn the top-right 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 2, R1C7, R1C8 and R1C9 cannot hold 2.- Because row 2 already has a 2, R2C9 cannot hold 2.- Because column 8 already has a 2, R3C8 cannot hold 2.- Because column 9 already has a 2, R3C9 cannot hold 2.So 2 must go in R3C7.
  7. R1C9 = 7 · Hidden SingleIn the top-right 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 7, R1C7 cannot hold 7.- Because column 8 already has a 7, R1C8 cannot hold 7.- Because row 2 already has a 7, R2C9 cannot hold 7.- Because row 3 already has a 7, R3C8 and R3C9 cannot hold 7.So 7 must go in R1C9.
  8. R6C5 = 2 · Hidden SingleIn the centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 2, R4C4 and R4C5 cannot hold 2.- Because row 5 already has a 2, R5C6 cannot hold 2.- Because column 4 already has a 2, R6C4 cannot hold 2.So 2 must go in R6C5.
  9. R6C4 = 7 · Hidden SingleIn the centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 7, R4C4 and R4C5 cannot hold 7.- Because row 5 already has a 7, R5C6 cannot hold 7.So 7 must go in R6C4.
  10. R7C3 = 2 · Hidden SingleIn the bottom-left 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 2 already has a 2, R7C2 cannot hold 2.- Because row 8 already has a 2, R8C1, R8C2 and R8C3 cannot hold 2.- Because row 9 already has a 2, R9C1 and R9C3 cannot hold 2.So 2 must go in R7C3.
  11. R7C2 = 7 · Hidden SingleIn the bottom-left 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 7, R8C1, R8C2 and R8C3 cannot hold 7.- Because row 9 already has a 7, R9C1 and R9C3 cannot hold 7.So 7 must go in R7C2.
  12. R9C3 = 9 · Hidden SingleIn the bottom-left 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 9, R8C1, R8C2 and R8C3 cannot hold 9.- Because column 1 already has a 9, R9C1 cannot hold 9.So 9 must go in R9C3.
  13. R7C9 = 1 · Hidden SingleIn the bottom-right 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 1, R7C7 and R8C7 cannot hold 1.- Because column 8 already has a 1, R7C8 and R8C8 cannot hold 1.- Because row 9 already has a 1, R9C7 cannot hold 1.So 1 must go in R7C9.
  14. R9C7 = 4 · Hidden SingleIn the bottom-right 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 4, R7C7 and R7C8 cannot hold 4.- Because row 8 already has a 4, R8C7 and R8C8 cannot hold 4.So 4 must go in R9C7.
  15. R1C8 = 4 · Hidden SingleIn the top-right 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 4, R1C7 cannot hold 4.- Because row 2 already has a 4, R2C9 cannot hold 4.- Because row 3 already has a 4, R3C8 and R3C9 cannot hold 4.So 4 must go in R1C8.
  16. R1C7 = 9 · Hidden SingleIn the top-right 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 9, R2C9 cannot hold 9.- Because row 3 already has a 9, R3C8 and R3C9 cannot hold 9.So 9 must go in R1C7.
  17. R1C6 = 8 · Naked SingleLooking at R1C6:- Row 1 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.
  18. R2C4 = 9 · Hidden SingleIn the top-centre 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 3 already has a 9, R3C6 cannot hold 9.So 9 must go in R2C4.
  19. R2C9 = 5 · Naked SingleLooking at R2C9:- Row 2 already has 1, 2, 3, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.
  20. R3C6 = 5 · Naked SingleLooking at R3C6:- Row 3 already has 1, 2, 4, 6, 7 and 9 → ruled out.- Column 6 already has 3 and 8 → ruled out.So this cell can only be 5.
  21. R4C5 = 9 · Hidden SingleIn the centre 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 9, R4C4 cannot hold 9.- Because row 5 already has a 9, R5C6 cannot hold 9.So 9 must go in R4C5.
  22. R4C4 = 5 · Hidden SingleIn the centre 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because column 6 already has a 5, R5C6 cannot hold 5.So 5 must go in R4C4.
  23. R7C4 = 6 · Naked SingleLooking at R7C4:- Row 7 already has 1, 2, 4 and 7 → ruled out.- Column 4 already has 3, 5, 8 and 9 → ruled out.So this cell can only be 6.
  24. R5C6 = 6 · Naked SingleLooking at R5C6:- Row 5 already has 1, 2, 4, 7, 8 and 9 → ruled out.- Column 6 already has 3 and 5 → ruled out.So this cell can only be 6.
  25. R7C6 = 9 · Naked SingleLooking at R7C6:- Row 7 already has 1, 2, 4, 6 and 7 → ruled out.- Column 6 already has 3, 5 and 8 → ruled out.So this cell can only be 9.
  26. R6C8 = 9 · Hidden SingleIn the middle-right 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 9, R4C7 and R4C9 cannot hold 9.- Because row 5 already has a 9, R5C9 cannot hold 9.- Because column 7 already has a 9, R6C7 cannot hold 9.So 9 must go in R6C8.
  27. R6C7 = 5 · Hidden SingleIn the middle-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 5, R4C7 and R4C9 cannot hold 5.- Because column 9 already has a 5, R5C9 cannot hold 5.So 5 must go in R6C7.
  28. R5C1 = 5 · Hidden SingleIn the middle-left 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 5, R4C3 cannot hold 5.- Because row 6 already has a 5, R6C1, R6C2 and R6C3 cannot hold 5.So 5 must go in R5C1.
  29. R5C9 = 3 · Naked SingleLooking at R5C9:- Row 5 already has 1, 2, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 3.
  30. R3C8 = 3 · Hidden SingleIn the top-right 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 3, R3C9 cannot hold 3.So 3 must go in R3C8.
  31. R3C9 = 8 · Naked SingleLooking at R3C9:- Row 3 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.
  32. R4C9 = 6 · Naked SingleLooking at R4C9:- Row 4 already has 1, 2, 4, 5, 7 and 9 → ruled out.- Column 9 already has 3 and 8 → ruled out.So this cell can only be 6.
  33. R4C7 = 8 · Naked SingleLooking at R4C7:- Row 4 already has 1, 2, 4, 5, 6, 7 and 9 → ruled out.- The middle-right 3×3 box already has 3 → ruled out.So this cell can only be 8.
  34. R4C3 = 3 · Naked SingleLooking at R4C3:- Row 4 already has 1, 2, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 3.
  35. R8C1 = 3 · Hidden SingleIn the bottom-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 2 already has a 3, R8C2 cannot hold 3.- Because column 3 already has a 3, R8C3 cannot hold 3.- Because row 9 already has a 3, R9C1 cannot hold 3.So 3 must go in R8C1.
  36. R7C5 = 5 · Hidden SingleIn the bottom-centre 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 9 already has a 5, R9C5 cannot hold 5.So 5 must go in R7C5.
  37. R9C5 = 8 · Naked SingleLooking at R9C5:- Row 9 already has 1, 2, 3, 4, 5, 7 and 9 → ruled out.- Column 5 already has 6 → ruled out.So this cell can only be 8.
  38. R9C1 = 6 · Naked SingleLooking at R9C1:- Row 9 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  39. R6C1 = 8 · Naked SingleLooking at R6C1:- Row 6 already has 2, 3, 4, 5, 7 and 9 → ruled out.- Column 1 already has 1 and 6 → ruled out.So this cell can only be 8.
  40. R6C3 = 6 · Hidden SingleIn the middle-left 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 2 already has a 6, R6C2 cannot hold 6.So 6 must go in R6C3.
  41. R6C2 = 1 · Naked SingleLooking at R6C2:- Row 6 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  42. R8C2 = 8 · Naked SingleLooking at R8C2:- Row 8 already has 2, 3, 4, 7 and 9 → ruled out.- Column 2 already has 1, 5 and 6 → ruled out.So this cell can only be 8.
  43. R8C3 = 1 · Naked SingleLooking at R8C3:- Row 8 already has 2, 3, 4, 7, 8 and 9 → ruled out.- Column 3 already has 5 and 6 → ruled out.So this cell can only be 1.
  44. R7C7 = 3 · Hidden SingleIn the bottom-right 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 8 already has a 3, R7C8 cannot hold 3.- Because row 8 already has a 3, R8C7 and R8C8 cannot hold 3.So 3 must go in R7C7.
  45. R7C8 = 8 · Naked SingleLooking at R7C8:- Row 7 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.
  46. R8C7 = 6 · Naked SingleLooking at R8C7:- Row 8 already has 1, 2, 3, 4, 7, 8 and 9 → ruled out.- Column 7 already has 5 → ruled out.So this cell can only be 6.
  47. R8C8 = 5 · Naked SingleLooking at R8C8:- Row 8 already has 1, 2, 3, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.

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