Skudo
ENVI
Play on web

Daily Sudoku — 16 September 2026

The puzzle

  • 16 September 2026
  • Medium
  • 34 clues
Puzzle
··7···28·
·5··9··36
361···7··
·9···3·1·
736··84··
·8·4··6··
4··861·52
·1··5234·
··9······
Solution
947136285
852794136
361285794
294673518
736518429
185429673
473861952
618952347
529347861

Solve it in the app to get on the board

Step-by-step solution

Every cell below is filled by the same hint engine the app uses, in the order it can be deduced — 47 steps using 2 techniques.

Techniques used

  • Hidden Single — inside one row, column or box this digit fits in only one cell, so it must go there
  • Naked Single — every other digit is already used in this cell's row, column or box, so only one candidate is left
  1. R1C1 = 9 · Hidden SingleIn the top-left 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because column 2 already has a 9, R1C2 cannot hold 9.- Because row 2 already has a 9, R2C1 and R2C3 cannot hold 9.So 9 must go in R1C1.
  2. R3C5 = 8 · Hidden SingleIn the top-centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 1 already has an 8, R1C4, R1C5 and R1C6 cannot hold 8.- Because column 4 already has an 8, R2C4 and R3C4 cannot hold 8.- Because column 6 already has an 8, R2C6 and R3C6 cannot hold 8.So 8 must go in R3C5.
  3. R6C1 = 1 · Hidden SingleIn the middle-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 1, R4C1 and R4C3 cannot hold 1.- Because column 3 already has a 1, R6C3 cannot hold 1.So 1 must go in R6C1.
  4. R4C3 = 4 · Hidden SingleIn the middle-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 4, R4C1 cannot hold 4.- Because row 6 already has a 4, R6C3 cannot hold 4.So 4 must go in R4C3.
  5. R1C2 = 4 · Hidden SingleIn the top-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 4, R2C1 cannot hold 4.- Because column 3 already has a 4, R2C3 cannot hold 4.So 4 must go in R1C2.
  6. R3C9 = 4 · Hidden SingleIn the top-right 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 4, R1C9 cannot hold 4.- Because column 7 already has a 4, R2C7 cannot hold 4.- Because column 8 already has a 4, R3C8 cannot hold 4.So 4 must go in R3C9.
  7. R2C6 = 4 · Hidden SingleIn the top-centre 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 4, R1C4, R1C5 and R1C6 cannot hold 4.- Because column 4 already has a 4, R2C4 cannot hold 4.- Because row 3 already has a 4, R3C4 and R3C6 cannot hold 4.So 4 must go in R2C6.
  8. R2C4 = 7 · Hidden SingleIn the top-centre 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 7, R1C4, R1C5 and R1C6 cannot hold 7.- Because row 3 already has a 7, R3C4 and R3C6 cannot hold 7.So 7 must go in R2C4.
  9. R3C4 = 2 · Hidden SingleIn the top-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 2, R1C4, R1C5 and R1C6 cannot hold 2.- Because column 6 already has a 2, R3C6 cannot hold 2.So 2 must go in R3C4.
  10. R1C9 = 5 · Hidden SingleIn the top-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 2 already has a 5, R2C7 cannot hold 5.- Because column 8 already has a 5, R3C8 cannot hold 5.So 5 must go in R1C9.
  11. R3C6 = 5 · Hidden SingleIn the top-centre 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 5, R1C4, R1C5 and R1C6 cannot hold 5.So 5 must go in R3C6.
  12. R3C8 = 9 · Naked SingleLooking at R3C8:- Row 3 already has 1, 2, 3, 4, 5, 6, 7 and 8 → ruled out.So this cell can only be 9.
  13. R2C7 = 1 · Naked SingleLooking at R2C7:- Row 2 already has 3, 4, 5, 6, 7 and 9 → ruled out.- Column 7 already has 2 → ruled out.- The top-right 3×3 box already has 8 → ruled out.So this cell can only be 1.
  14. R4C4 = 6 · Hidden SingleIn the centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 5 already has a 6, R4C5 cannot hold 6.- Because row 5 already has a 6, R5C4 and R5C5 cannot hold 6.- Because row 6 already has a 6, R6C5 and R6C6 cannot hold 6.So 6 must go in R4C4.
  15. R1C6 = 6 · Hidden SingleIn the top-centre 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 4 already has a 6, R1C4 cannot hold 6.- Because column 5 already has a 6, R1C5 cannot hold 6.So 6 must go in R1C6.
  16. R5C4 = 5 · Hidden SingleIn the centre 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because column 5 already has a 5, R4C5, R5C5 and R6C5 cannot hold 5.- Because column 6 already has a 5, R6C6 cannot hold 5.So 5 must go in R5C4.
  17. R5C5 = 1 · Hidden SingleIn the centre 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 1, R4C5 cannot hold 1.- Because row 6 already has a 1, R6C5 and R6C6 cannot hold 1.So 1 must go in R5C5.
  18. R1C4 = 1 · Hidden SingleIn the top-centre 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because column 5 already has a 1, R1C5 cannot hold 1.So 1 must go in R1C4.
  19. R1C5 = 3 · Naked SingleLooking at R1C5:- Row 1 already has 1, 2, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 3.
  20. R6C6 = 9 · Hidden SingleIn the centre 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 9, R4C5 cannot hold 9.- Because column 5 already has a 9, R6C5 cannot hold 9.So 9 must go in R6C6.
  21. R9C6 = 7 · Naked SingleLooking at R9C6:- Row 9 already has 9 → ruled out.- Column 6 already has 1, 2, 3, 4, 5, 6 and 8 → ruled out.So this cell can only be 7.
  22. R6C9 = 3 · Hidden SingleIn the middle-right 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 3, R4C7 and R4C9 cannot hold 3.- Because row 5 already has a 3, R5C8 and R5C9 cannot hold 3.- Because column 8 already has a 3, R6C8 cannot hold 3.So 3 must go in R6C9.
  23. R4C7 = 5 · Hidden SingleIn the middle-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 5, R4C9 cannot hold 5.- Because row 5 already has a 5, R5C8 and R5C9 cannot hold 5.- Because column 8 already has a 5, R6C8 cannot hold 5.So 5 must go in R4C7.
  24. R6C3 = 5 · Hidden SingleIn the middle-left 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 5, R4C1 cannot hold 5.So 5 must go in R6C3.
  25. R4C1 = 2 · Naked SingleLooking at R4C1:- Row 4 already has 1, 3, 4, 5, 6 and 9 → ruled out.- Column 1 already has 7 → ruled out.- The middle-left 3×3 box already has 8 → ruled out.So this cell can only be 2.
  26. R2C3 = 2 · Hidden SingleIn the top-left 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 2, R2C1 cannot hold 2.So 2 must go in R2C3.
  27. R2C1 = 8 · Naked SingleLooking at R2C1:- Row 2 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.
  28. R6C5 = 2 · Hidden SingleIn the centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 2, R4C5 cannot hold 2.So 2 must go in R6C5.
  29. R6C8 = 7 · Naked SingleLooking at R6C8:- Row 6 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  30. R4C5 = 7 · Naked SingleLooking at R4C5:- Row 4 already has 1, 2, 3, 4, 5, 6 and 9 → ruled out.- Column 5 already has 8 → ruled out.So this cell can only be 7.
  31. R4C9 = 8 · Naked SingleLooking at R4C9:- Row 4 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.
  32. R9C5 = 4 · Naked SingleLooking at R9C5:- Row 9 already has 7 and 9 → ruled out.- Column 5 already has 1, 2, 3, 5, 6 and 8 → ruled out.So this cell can only be 4.
  33. R5C8 = 2 · Hidden SingleIn the middle-right 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because column 9 already has a 2, R5C9 cannot hold 2.So 2 must go in R5C8.
  34. R5C9 = 9 · Naked SingleLooking at R5C9:- Row 5 already has 1, 2, 3, 4, 5, 6, 7 and 8 → ruled out.So this cell can only be 9.
  35. R9C8 = 6 · Naked SingleLooking at R9C8:- Row 9 already has 4, 7 and 9 → ruled out.- Column 8 already has 1, 2, 3, 5 and 8 → ruled out.So this cell can only be 6.
  36. R9C2 = 2 · Hidden SingleIn the bottom-left 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 2, R7C2 and R7C3 cannot hold 2.- Because row 8 already has a 2, R8C1 and R8C3 cannot hold 2.- Because column 1 already has a 2, R9C1 cannot hold 2.So 2 must go in R9C2.
  37. R7C2 = 7 · Naked SingleLooking at R7C2:- Row 7 already has 1, 2, 4, 5, 6 and 8 → ruled out.- Column 2 already has 3 and 9 → ruled out.So this cell can only be 7.
  38. R7C3 = 3 · Hidden SingleIn the bottom-left 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 3, R8C1 and R8C3 cannot hold 3.- Because column 1 already has a 3, R9C1 cannot hold 3.So 3 must go in R7C3.
  39. R7C7 = 9 · Naked SingleLooking at R7C7:- Row 7 already has 1, 2, 3, 4, 5, 6, 7 and 8 → ruled out.So this cell can only be 9.
  40. R8C3 = 8 · Naked SingleLooking at R8C3:- Row 8 already has 1, 2, 3, 4 and 5 → ruled out.- Column 3 already has 6, 7 and 9 → ruled out.So this cell can only be 8.
  41. R9C7 = 8 · Naked SingleLooking at R9C7:- Row 9 already has 2, 4, 6, 7 and 9 → ruled out.- Column 7 already has 1, 3 and 5 → ruled out.So this cell can only be 8.
  42. R9C1 = 5 · Hidden SingleIn the bottom-left 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 5, R8C1 cannot hold 5.So 5 must go in R9C1.
  43. R8C1 = 6 · Naked SingleLooking at R8C1:- Row 8 already has 1, 2, 3, 4, 5 and 8 → ruled out.- Column 1 already has 7 and 9 → ruled out.So this cell can only be 6.
  44. R9C4 = 3 · Hidden SingleIn the bottom-centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 3, R8C4 cannot hold 3.So 3 must go in R9C4.
  45. R9C9 = 1 · Naked SingleLooking at R9C9:- Row 9 already has 2, 3, 4, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 1.
  46. R8C4 = 9 · Naked SingleLooking at R8C4:- Row 8 already has 1, 2, 3, 4, 5, 6 and 8 → ruled out.- Column 4 already has 7 → ruled out.So this cell can only be 9.
  47. R8C9 = 7 · Naked SingleLooking at R8C9:- Row 8 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.

First to finish

Ranked by when each player finished, not by how long they took — so looking up a solution never moves anyone up this board.

Open the app to see who finished first.

Recent days

Full archive →