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Daily Sudoku — 4 August 2026

The puzzle

  • 4 August 2026
  • Easy
  • 40 clues
Puzzle
1···2···8
4·61·9·27
··2·6···9
·57·84··1
2··69·3··
6·····284
8619·3··2
72·81·953
9······1·
Solution
193527468
486139527
572468139
357284691
248691375
619375284
861953742
724816953
935742816

Solve it in the app to get on the board

Step-by-step solution

Every cell below is filled by the same hint engine the app uses, in the order it can be deduced — 41 steps using 2 techniques.

Techniques used

  • Hidden Single — inside one row, column or box this digit fits in only one cell, so it must go there
  • Naked Single — every other digit is already used in this cell's row, column or box, so only one candidate is left
  1. R3C6 = 8 · Hidden SingleIn the top-centre 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 8, R1C4 and R1C6 cannot hold 8.- Because column 5 already has a 8, R2C5 cannot hold 8.- Because column 4 already has a 8, R3C4 cannot hold 8.So 8 must go in R3C6.
  2. R2C2 = 8 · Hidden SingleIn the top-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 8, R1C2 and R1C3 cannot hold 8.- Because row 3 already has a 8, R3C1 and R3C2 cannot hold 8.So 8 must go in R2C2.
  3. R3C7 = 1 · Hidden SingleIn the top-right 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 1, R1C7 and R1C8 cannot hold 1.- Because row 2 already has a 1, R2C7 cannot hold 1.- Because column 8 already has a 1, R3C8 cannot hold 1.So 1 must go in R3C7.
  4. R5C3 = 8 · Hidden SingleIn the middle-left 3×3 box, 8 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 8, R4C1 cannot hold 8.- Because column 2 already has a 8, R5C2 cannot hold 8.- Because row 6 already has a 8, R6C2 and R6C3 cannot hold 8.So 8 must go in R5C3.
  5. R5C2 = 4 · Hidden SingleIn the middle-left 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 4, R4C1 cannot hold 4.- Because row 6 already has a 4, R6C2 and R6C3 cannot hold 4.So 4 must go in R5C2.
  6. R6C2 = 1 · Hidden SingleIn the middle-left 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 1, R4C1 cannot hold 1.- Because column 3 already has a 1, R6C3 cannot hold 1.So 1 must go in R6C2.
  7. R6C3 = 9 · Hidden SingleIn the middle-left 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because column 1 already has a 9, R4C1 cannot hold 9.So 9 must go in R6C3.
  8. R4C1 = 3 · Naked SingleLooking at R4C1:- Row 4 already has 1, 4, 5, 7 and 8 → ruled out.- Column 1 already has 2, 6 and 9 → ruled out.So this cell can only be 3.
  9. R3C1 = 5 · Naked SingleLooking at R3C1:- Row 3 already has 1, 2, 6, 8 and 9 → ruled out.- Column 1 already has 3, 4 and 7 → ruled out.So this cell can only be 5.
  10. R1C2 = 9 · Hidden SingleIn the top-left 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because column 3 already has a 9, R1C3 cannot hold 9.- Because row 3 already has a 9, R3C2 cannot hold 9.So 9 must go in R1C2.
  11. R3C2 = 7 · Hidden SingleIn the top-left 3×3 box, 7 fits in only one cell. Looking at the other empty cells:- Because column 3 already has a 7, R1C3 cannot hold 7.So 7 must go in R3C2.
  12. R9C2 = 3 · Naked SingleLooking at R9C2:- Row 9 already has 1 and 9 → ruled out.- Column 2 already has 2, 4, 5, 6, 7 and 8 → ruled out.So this cell can only be 3.
  13. R1C3 = 3 · Naked SingleLooking at R1C3:- Row 1 already has 1, 2, 8 and 9 → ruled out.- Column 3 already has 6 and 7 → ruled out.- The top-left 3×3 box already has 4 and 5 → ruled out.So this cell can only be 3.
  14. R3C8 = 3 · Hidden SingleIn the top-right 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 3, R1C7 and R1C8 cannot hold 3.- Because column 7 already has a 3, R2C7 cannot hold 3.So 3 must go in R3C8.
  15. R3C4 = 4 · Naked SingleLooking at R3C4:- Row 3 already has 1, 2, 3, 5, 6, 7, 8 and 9 → ruled out.So this cell can only be 4.
  16. R2C5 = 3 · Hidden SingleIn the top-centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because row 1 already has a 3, R1C4 and R1C6 cannot hold 3.So 3 must go in R2C5.
  17. R2C7 = 5 · Naked SingleLooking at R2C7:- Row 2 already has 1, 2, 3, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.
  18. R5C6 = 1 · Hidden SingleIn the centre 3×3 box, 1 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 1, R4C4 cannot hold 1.- Because row 6 already has a 1, R6C4, R6C5 and R6C6 cannot hold 1.So 1 must go in R5C6.
  19. R4C4 = 2 · Hidden SingleIn the centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 6 already has a 2, R6C4, R6C5 and R6C6 cannot hold 2.So 2 must go in R4C4.
  20. R6C4 = 3 · Hidden SingleIn the centre 3×3 box, 3 fits in only one cell. Looking at the other empty cells:- Because column 5 already has a 3, R6C5 cannot hold 3.- Because column 6 already has a 3, R6C6 cannot hold 3.So 3 must go in R6C4.
  21. R5C9 = 5 · Hidden SingleIn the middle-right 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 4 already has a 5, R4C7 and R4C8 cannot hold 5.- Because column 8 already has a 5, R5C8 cannot hold 5.So 5 must go in R5C9.
  22. R5C8 = 7 · Naked SingleLooking at R5C8:- Row 5 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  23. R9C9 = 6 · Naked SingleLooking at R9C9:- Row 9 already has 1, 3 and 9 → ruled out.- Column 9 already has 2, 4, 5, 7 and 8 → ruled out.So this cell can only be 6.
  24. R4C8 = 9 · Hidden SingleIn the middle-right 3×3 box, 9 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 9, R4C7 cannot hold 9.So 9 must go in R4C8.
  25. R4C7 = 6 · Naked SingleLooking at R4C7:- Row 4 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  26. R1C8 = 6 · Hidden SingleIn the top-right 3×3 box, 6 fits in only one cell. Looking at the other empty cells:- Because column 7 already has a 6, R1C7 cannot hold 6.So 6 must go in R1C8.
  27. R7C8 = 4 · Naked SingleLooking at R7C8:- Row 7 already has 1, 2, 3, 6, 8 and 9 → ruled out.- Column 8 already has 5 and 7 → ruled out.So this cell can only be 4.
  28. R1C7 = 4 · Naked SingleLooking at R1C7:- Row 1 already has 1, 2, 3, 6, 8 and 9 → ruled out.- Column 7 already has 5 → ruled out.- The top-right 3×3 box already has 7 → ruled out.So this cell can only be 4.
  29. R9C3 = 5 · Hidden SingleIn the bottom-left 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 8 already has a 5, R8C3 cannot hold 5.So 5 must go in R9C3.
  30. R8C3 = 4 · Naked SingleLooking at R8C3:- Row 8 already has 1, 2, 3, 5, 7, 8 and 9 → ruled out.- Column 3 already has 6 → ruled out.So this cell can only be 4.
  31. R8C6 = 6 · Naked SingleLooking at R8C6:- Row 8 already has 1, 2, 3, 4, 5, 7, 8 and 9 → ruled out.So this cell can only be 6.
  32. R9C6 = 2 · Hidden SingleIn the bottom-centre 3×3 box, 2 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 2, R7C5 cannot hold 2.- Because column 4 already has a 2, R9C4 cannot hold 2.- Because column 5 already has a 2, R9C5 cannot hold 2.So 2 must go in R9C6.
  33. R9C5 = 4 · Hidden SingleIn the bottom-centre 3×3 box, 4 fits in only one cell. Looking at the other empty cells:- Because row 7 already has a 4, R7C5 cannot hold 4.- Because column 4 already has a 4, R9C4 cannot hold 4.So 4 must go in R9C5.
  34. R7C5 = 5 · Hidden SingleIn the bottom-centre 3×3 box, 5 fits in only one cell. Looking at the other empty cells:- Because row 9 already has a 5, R9C4 cannot hold 5.So 5 must go in R7C5.
  35. R7C7 = 7 · Naked SingleLooking at R7C7:- Row 7 already has 1, 2, 3, 4, 5, 6, 8 and 9 → ruled out.So this cell can only be 7.
  36. R6C5 = 7 · Naked SingleLooking at R6C5:- Row 6 already has 1, 2, 3, 4, 6, 8 and 9 → ruled out.- Column 5 already has 5 → ruled out.So this cell can only be 7.
  37. R6C6 = 5 · Naked SingleLooking at R6C6:- Row 6 already has 1, 2, 3, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.
  38. R1C6 = 7 · Naked SingleLooking at R1C6:- Row 1 already has 1, 2, 3, 4, 6, 8 and 9 → ruled out.- Column 6 already has 5 → ruled out.So this cell can only be 7.
  39. R1C4 = 5 · Naked SingleLooking at R1C4:- Row 1 already has 1, 2, 3, 4, 6, 7, 8 and 9 → ruled out.So this cell can only be 5.
  40. R9C4 = 7 · Naked SingleLooking at R9C4:- Row 9 already has 1, 2, 3, 4, 5, 6 and 9 → ruled out.- Column 4 already has 8 → ruled out.So this cell can only be 7.
  41. R9C7 = 8 · Naked SingleLooking at R9C7:- Row 9 already has 1, 2, 3, 4, 5, 6, 7 and 9 → ruled out.So this cell can only be 8.

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